On the Condensing of Alpha-Bits
An advert for cereal? Count me in.
For those familiar with the original manual.
0 | 00000 | 8 | 01000 | G | 10000 | O | 11000 |
---|---|---|---|---|---|---|---|
1 | 00001 | 9 | 01001 | H | 10001 | P | 11001 |
2 | 00010 | A | 01010 | I | 10010 | Q | 11010 |
3 | 00011 | B | 01011 | J | 10011 | R | 11011 |
4 | 00100 | C | 01100 | K | 10100 | S | 11100 |
5 | 00101 | D | 01101 | L | 10101 | T | 11101 |
6 | 00110 | E | 01110 | M | 10110 | U | 11110 |
7 | 00111 | F | 01111 | N | 10111 | V | 11111 |
X corresponds to the bit to the left of the operator used; Y corresponds to the bit to the right.
Inputs | Digits -> Operators | ||||||||
---|---|---|---|---|---|---|---|---|---|
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | ||
X | Y | OR | AND | XOR | IMP | NOR | NAND | XNOR | IMPBY |
1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 |
1 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 1 |
0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 |