A | 00000 |
---|---|
B | 00001 |
C | 00010 |
D | 00011 |
E | 00100 |
F | 00101 |
G | 00110 |
H | 00111 |
I | 01000 |
J | 01001 |
K | 01010 |
L | 01011 |
M | 01100 |
N | 01101 |
O | 01110 |
P | 01111 |
Q | 10000 |
R | 10001 |
S | 10010 |
T | 10011 |
U | 1010 |
V | 1011 |
W | 1100 |
X | 1101 |
Y | 1110 |
Z | 1111 |
On the Subject of Blue Huffman Ciphers
Colored like Ravenclaw, still sounds like Hufflepuff.
This module contains 3 screens, a keyboard, 2 arrows, and a submit button that displays the current page you’re on.
Pressing the left or right arrow takes you to the previous or next page. There are 2 pages.
To disarm the module, decrypt a word using the following three steps. Once you have the decrypted word, type it in using the keyboard. When you start typing, the screens go blank and the bottom screen will show what you are typing.
To clear your input, click one of the arrows.
Once you are satisfied with your input, press the button labeled “SUB” to submit your answer.
Step 1: Huffman Tree Construction
For this step, use all the letters on the top, middle and bottom screens on page 1 and the top and middle screens on page 2 (in that order). This gives a 26-letter code. Convert the letters into their alphabetic positions to obtain a list of 26 “scores”. Associate the first with the letter A, then B, etc., up to Z.
Find the two entries with the lowest scores. In case of ties, take the earliest in the list. Create a new entry at the end of the list whose score is the sum of the scores of the two entries. The new entry is a binary tree whose left child node is the entry with the lowest score (or earliest if tied) and the right child node is the other one. Remove the two original entries from the list.
Repeat this a total of 25 times, iteratively reducing the list to a single binary tree.
The next page illustrates these steps with an example.
Step 2: Encrypted Binary Retrieval
Convert the encoded word from the third screen on page 2 to a single binary string by replacing each letter with a binary code from the table on the right.