On the Subject of Homophonic CM
A machine that knows no bounds when it comes to ciphers.
Config the table below so that the lowest value in that row is underneath the letter that is shown on screen A. Ex: OEC means that 01 is under O, 27 is under E, and 53 is under C.
For each letter of the encrypted word, do the following.
- Take the Nth digit of the digit string on screen 1.
- Take the Nth letter of the encrypted word and modulo it by 10.
- Treat the 1st number you got as the tens place and the 2nd number as the ones place.
- Find the number in the table you configured to decrypt to a letter that is above the row of numbers.
You should now have a decrypted word.
For each number, find them in the table and use the column of the number to get the letter that is above the rows of numbers.
You should now have a decrypted keyword that will be used in step 3 so hang on to it.
Encrypted Word: MQNVG
Digit String: 50072
5 + M → 53 → C
0 + Q → 07 → U
0 + N → 04 → R
7 + V → 72 → V
2 + G → 27 → E
Decrypted Word: CURVE