Discolored Cube

On the Subject of Discolored Cube

Honestly, yeah just figure it out.

See Appendix CLC-DLC for identifying Colored Cube variants.

For people who are familiar with the original manual.

Whenever this manual says L/R or U/D, it refers to the directions available to you.

Value = 1

Y

B

M

G

C

R

Value = 2

B

C

Y

M

G

R

Value = 3

R

M

C

G

Y

B

Value = 4

Y

B

G

M

C

R

Value = 5

C

Y

G

M

R

B

Value = 6

G

C

B

Y

R

M

Value = 7

B

G

Y

C

M

R

Value = 8

Y

M

B

R

G

C

Value = 9

Y

G

B

R

C

M

Value = 10

G

C

M

R

Y

B

Value = 11

C

M

B

R

G

Y

Value = 12

G

M

R

C

Y

B

Step 1: Using Your Starting Position

Make a template like this:

1-

2-

3-

4-

5-

6-

Write down the top left number on the cube and the initial color. Click L/R once. Then, click U/D once. This will change the color.

Figure out the possible strip values still available for your initial strip, using the two colors you already have. For example, if your initial cube was red, and one left was a magenta, the initial strip could be 5, 7, 10, and 12.

Step 2: Cycling Colors

Remember that appended colors are added to the end of the strip, and they can still be moved on when you cycle.

If you found the initial strip value at this point, you can skip to step 3, and put the strip value next to the initial cube value row. Otherwise, every time you go U/D, add +(Current Color of Cube) to the row of the previous number. For example, if I went up from 4 to 3 and the cube is now Magenta, I would have 4- +M

Keep cycling colors until you are one before the initial cube value! From there, you cannot simply click U/D since it will enter submission mode. Instead, you need to go L/R (6 + the amount of colors appended to the current strip). This will keep you in the same column, where you can click U/D one more time to return to the initial strip.

Step 2.5: Find Initial Strip Value

Now that you have some possible strip values for the initial strip, do process of elimination to limit it down to one strip. With the previous example, from 5, 7, 10, and 12 on a Magenta, I go three left to get Cyan. Therefore, the initial strip must be 5.

If you could not figure out the initial strip, repeat steps 2 and 2.5 until you have.

Step 3: Finding the Rest of the Strips

Now that you know the initial strip value, all of the colors of the other strips are relative to the initial one. For example, if the initial was valued 5, and the color we started cycling on was magenta, all the rest of the appended colors were in Column 4.

With these example notes:

Initial: 2 Red, Directions U and L

1- +Y

2- (5) +M

3- +R

4- +C

5- +G

6- +G

You can modify your notes to this:

1- (6) +Y

2- (5) +M

3- (10, 8, 11, 9) +R

4- (7, 12) +C

5- (1, 3) +G

6- (1, 3) +G

Go L/R once and cycle, using process of elimination, to figure out the rest of the strips. Every time you click up five times without pressing L/R, before you click up for the 6th time, go L/R (6 + the amount of colors appended to the current strip).

Step 4: Solving

Once you have all 6 strip values, press U/D until you hear an unique clicking noise. To get the colors to submit, go through each strip value. Look at the opposite strip value (1 and 6, 2 and 5, 3 and 4, etc.) Modulo that value by 6, and add 1. In the current strip, look at the color at that index. For example, If Strip 1 = 6 and Strip 6 = 11, your color to submit for Strip 1 is Magenta.

You either start at Strip 1 or Strip 6 depending if your movement is U or D. In each strip, cycle to the color you need to submit, and press U/D to submit it. Every time you move U or D you start at the same column. Submit all six colors to solve the module.