On the Subject of Multicolored Switches
"AAAAA AAAAA! MY EYES! SOO MANY COLORS!"
See Appendix of Colored Switches for identifying modules in Colored Switches family.
- This module will have five colored switches with colored sockets, 10 LEDs that will flash constantly with two colors, and a tiny LED in the middle to indicate in which cycle the LEDs are showing.
- To solve this module, you need to flip the switches until you reach a "solved" state.
- Trying to flip any switch to set the switches to a "wrong" state will give you a strike.
Identifying the sets:
- The LEDs will flash one of 7 colors or will be off (red, green, blue, magenta, yellow, cyan, white).
- The switches and sockets will be colored with one of 8 colors (red, green, blue, magenta, yellow, cyan, white, black)
- The LEDs, switches and sockets colors are actually a mixture of red, green or blue light. (Check Appendix: C0L0R5)
- The LEDs will flash the first cycle when the tiny led is on and the second if it's not.
- When decomposing the LEDs colors into primary color components (R G B), each row of 5 LEDs will create a set.
- Each set has three states (R G B).
- You will always have 4 sets with 3 different states (R,G,B).
- The rules below will tell which state is a "solve" ,"ignored" and "wrong" state.
Solving the module:
Finding the correct set:
- Count the number of red, green and blue coloring in all of the switches.
- Then find the color with the minimum and the other with the maximum amount of coloring.
- (If two colors shares the same max/min value, take the first one in this order (R G B))
- (Else if all are equal, then take red as your minimum and maximum color)
- Find the two states with the corresponding color that have more or less lit LEDs based on the color(s) you found.
- If they both share parity, then the "solve" and "ignored" states must be in the set that has the minimum one.
- Else they will be in the set that has the maximum.