On the Subject of Not Really Quaternions At All

*puts some mathematical terms* BOOSH! The module is now impossible.

First things first: if you see i2 = j2 = k2 = ijk = -1 on the module, then you are good.

Make a list with 4 numbers. We will call these [a, b, c, d] from now on.

Each number in this list has a number and a color.

Fill the two lists as follows:

  • Each spot has the color of the symbols in the formula in this order:

    [-1, i, j, k]

  • Duplicate the list.
  • Look at the module's buttons. For each pair of colors, fill in the first list with the largest number of the pair in the respective colored spot on the list.
  • Same with the second list, but with the lowest numbers
    NOTE: treat 0 as 10 when doing this.

Now, you have to swap the numbers with the same color if its corresponding condition applies:

Either i or j is red.
The bomb has at least one PS/2 port.
The bomb's serial number contains a letter in the word BLUE.
The sum of the two white keys is prime.

Now, some final touches to the lists:

  • Substitute "0" by "10".
  • If any number appears in the serial number (either one or more times), multiply that number by -1.
    Don't forget doing that with the 10 (if you have it) in case there is a 0 in the s#.
  • If no lit indicators, multiply first list's b, c and d by -1.
    Same with the second list in case of no unlit ones.
  • If there is an even number of batteries, swap the lists.

For the final step, let's label all the first and second lists' numbers:

[a1, b1, c1, d1] and [a2, b2, c2, d2]

Look at the color of the submit button, then look at which position is that color on any list; apply the formula depending on the position and submit that number:

1 ⇒ (a1*a2 - b1*b2 - c1*c2 - d1*d2)
2 ⇒ (a1*b2 + b1*a2 + c1*d2 - d1*c2)
3 ⇒ (a1*c2 - b1*d2 + c1*a2 + d1*b2)
4 ⇒ (a1*d2 + b1*c2 - c1*b2 + d1*a2)
White ⇒ (a12 + b12 + c12 + d12) * (a22 + b22 + c22 + d22)


Say, you have the following keypad:

i2 = j2 = k2 = i j k = -1
7 8 9
4 5 6
1 2 3

The colors of the list should be [   ,   ,   ,    ]

The first list should be [ 8, 9, 0, 4 ]

The second list should be [ 7, 5, 1, 2 ]

Then, in our example, let's say the serial number is 136AS8, we haven't got any unlit indicators, we have a PS/2 port, and the submit button is blue, therefore the lists should be:

[ -8, 9, -1, 4 ] and [ 7, -5, -10, -2 ]

Recall we just did:

  • Green applied ⇒ swap greens from the lists
  • "0" ⇒ "10"
  • 1 and 8 in s# ⇒ multiply them by -1 in the lists
  • No unlit indicators ⇒ multiply b, c and d in the second list by -1

The submit button is blue, so we use the first formula, thus the answer is "-13".